[(x-3) (2x +12=3(x+5)
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Answered by
3
Answer:
(x-3)(2x+12)=3(x+5)
x(2x+12)-3(2x+12)=3x+15
2x^2+12x-6x-36=3x+15
2x^2+6x-36=3x+15
2x^2+6x-36-3x-15=0
2x^2+3x-51=0
now above equation is a Quadratic equation
Answered by
0
Answer:
equation :- (x-3) (2x+12 = 3(x+5)
= (x-3) (2x+12 = 3x+15
= x(2x+12)-3(2x+12) = 3x+15
= 2x²+12x-6x-36 = 3x+15
= 2x²+6x-36 = 3x+15
= 2x²+6x-3x = 15+36
= 2x²+3x = 51
= 2x²+3x+51=0
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