(x^3-2x^2+5x-7) x (2x). ^2-3x+4
Answers
Answered by
1
Step-by-step explanation:
STEP
1
:
Equation at the end of step 1
((2x2 + 3x) - 4) - (x2 - 5x + 7)
STEP
2
:
Trying to factor by splitting the middle term
2.1 Factoring x2+8x-11
The first term is, x2 its coefficient is 1 .
The middle term is, +8x its coefficient is 8 .
The last term, "the constant", is -11
Step-1 : Multiply the coefficient of the first term by the constant 1 • -11 = -11
Step-2 : Find two factors of -11 whose sum equals the coefficient of the middle term, which is 8 .
-11 + 1 = -10
-1 + 11 = 10
Observation : No two such factors can be found !!
Conclusion : Trinomial can not be factored
Final result :
x2 + 8x - 11
Answered by
0
Answer:
3x4-10x3+23x2-41x+28
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