Question

x^3 - 2x^2 -x +2 factorize​

Answer 1

Answer:

(x+1)(x-2)(x-1)

Explanation:

let f(x)=x^3-2x^2-x+2

factors of constant are +/- 1 and +/- 2

let x+1=0

x= -1

f(-1)= -1^3-2(-1^2)-(-1)+2

-1-2+1+2

-3+3=0

hence , x+1 is a factor of f(×)

so, x^3-2x^2-x+2÷x+1

= x^2-3x+2

then, f(x)=(x+1)(x^2-3x+2)

= (x+1)(x^2-2x-x+2)

= (x+1) {x(x-2)-1(x-2)

= (x+1)(x-2)(x-1) ans.

Answer 2

Answer:

x^3 - 2x - x + 2

x^3 - x^2 +x + 2

x^2(x-2) (x^2-1) = (x-2) (x+2) (x-1)

I hope, it's helpful for you