Question

x=3¼ + 3-¼ and y = 3¼+3-¼ then the value of 3(x²+y²)² will be ​

Answer 1

Answer:

8x^3

Step-by-step explanation:

(x - y)^3 + (x + y)^3 +3(x - y)^2(x + y) +3(x + y)²(x - y)

let (x-y) = a

and (x+y) = b

now, replace (x-y) with a and (x+y) with b.

we have,

a^3 + b^3 + 3a^2b + 3ab^2

now apply identity (a+b)^3 = a^3 + b^3 +3a^2b + 3ab^2

= (a+b)^3

again replace a by (x-y)

and b by (x+y)

we have,

(a+b)^3 = (x-y+x+y)^3

           = (2x)^3

           =  8x^3

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