Math, asked by annanrichard987, 8 months ago

X^3+ 3^x=17 solve for the value of x

Answers

Answered by avoz
3

Answer:

Here is your answer:

x=2

Step-by-step explanation:

Consider the equation,

 {x}^{3}  +  {3}^{x}  = 17

we have to take such a number whose cube when sumed with 3 with the power of that number result as the number 17

let's take cases:

Case 1:

supose x=1

 {1}^{3}  +  {3}^{1} \:  should \: be \: \:  = 17

which is never possible because ( 1 + 3 ) = 4 which is not = 17.

Case 2:

suppose x=2

 {2}^{3}  +  {3}^{2}  = 17

8 + 9 = 17

17 = 17

hence, here we should stop as we get the value of x i.e.

x = 2

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