Question

(x+3)/3-(x-2)/2=1.And find s if 1/x+s=1​

Answer 1

Answer:

$\frac{5}{6}$

Step-by-step explanation:

$\frac{x + 3}{3} - \frac{x - 2}{2} = 1 \\ = > \frac{2(x + 3) - 3(x - 2)}{6} = 1 \\ = > \frac{2x + 6 - 3x + 6}{6} = 1 \\ = > \frac{12 - x}{6} = 1 \\ = > 12 - x = 6 \\ = > x = 12 - 6 \\ = > x = 6$

And,

$\frac{1}{x} + s = 1$

$= > \frac{1}{6} + s = 1 \\ = > s = 1 - \frac{1}{6} \\ = > s = \frac{6 - 1}{6} \\ = > s =\frac{5}{6}$