x= 3+√3 এবং xy= 6 হলে (x+y)^2 এর মান নির্ণয় কর
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a = {(2 – √3)/(2 + √3) (2 – √3 )} = 2 – √3
b = {(2 + √3)/ (2 – √3) (2 + √3)) = 2 + √3
∴ (1/a + 1) + (1/b + 1) = {1/(3 – √3)} + {1/(3 + √3)} = (3 + √3 + 3 – √3)/{(3 – √3) (3 + √3)} = 1
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answer is 5
hope it helpful
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