Question

(x+3) (3x+1) solve using (x+a) (x+b) identity​

Answer 1

Answer:

Using the identity is (m+a)(m+b)=m

2

+m(a+b)+ab.

Given: (3x−3)(3x+4) we apply the above identity by taking

m=3x, a=−3 and b=4

We get,

(3x−3)(3x+4)=(3x)

2

+(3x)(−3+4)+(−3×4)=9x

2

+(3x)(1)−12=9x

2

+3x−12

Hence, (3x−3)(3x+4)=9x

2

+3x−12.

Answer 2

Step-by-step explanation:

3x^2+x+9x+3=0

3x^2+10x+3=0

3x^2+9x+x+3=0

3x(x+3)+1(x+3)=0

(3x+1)(x+3)=0

x=(-1/3)-3