Question

x^3+3x^2+2x=1716

plz solve this equation​

Answer 1

Answer:

Let x, x + 1, x + 2 be the three integers

Then, x(x + 1)(x + 2) = -1716

x(x2 + 3x + 2) = -1716

x3 + 3x2 + 2x + 1716 = 0

By trial and error, -13 is a root:

-13⌋ 1      3     2       1716

                    130    -1716            

      1    -10    132      0

x3 + 3x2 + 2x + 1716 = (x + 13)(x2 -10x + 132)

The roots of x2 - 10x + 132 are not real numbers

So, x = -13

The numbers are -13, -12, -11

Answer 2

Answer:

x*(x+1)*(x+2)=1716

Three solutions were found :

x = 11

x =(-14-√-428)/2=-7-i√ 107 = -7.0000-10.3441i

x =(-14+√-428)/2=-7+i√ 107 = -7.0000+10.344i

Step-by-step explanation: