x ^3+ 3x^2
+ 3x + 1 is divided by x+1
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11
Answer:
Thus remainder is 4
Step-by-step explanation:
By remainder theorem
x+1=0
x=−1
p(x)=x^3 +3x^2 −3x−1p(−1)
=(−1)^3 +3(−1)^2 −3(−1)−1
=−1+3(1)+3−1
=−1+3+3−1
=6−2
=4
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