X^3+3x^2+3x+1÷x+π
Please solve this class 9 polynomials
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p(π)
Step-by-step explanation: By the Remainder Theorem, the remainder when a polynomial p(x) is divided by a polynomial x-a, is p(a). Taking a=(-π), we get the remainder as p(π) =(-π)^3 +3(-π)^2 +3(-π)+1 = -π^3 +3π^2 -3π +1(= (1-π)^3 )
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