X^3+3x^2-4x-12=? Hint p(2)=0
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Step-by-step explanation:
since p(2)=0
this implies that x-2 is the factor of above polynomial
Dividing the polynomial by x-2
x^2+5x+6
x^2+2x+3x+6
X(x+2)+3(x+2)
(x+2)(x+3)
therefore the factors.of the polynomial is
(x-2)(x+3)(x+2)
(x^2-4)(x+3)[using (a-b)(a+b)= a^2-b^2]
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