Question

x^3-3x^2+4x+k is exactly divided by (x-2) find k​

Answer 1

x^3-3x^2+4x+k is exactly divided by (x-2) find k = 4

x³-3x²+4x+k

8-12+8+k=0

-4+8=k

k=4

Answer 2

Answer:

If it is exactly divisible by (x-2), then x = 2 is one of its zeroes.

Therefore, 2³-3(2)²+4(2)+k = 0

8 - 12 + 8 + k = 0

4 + k = 0

k = -4