Question

x^3-3x^2+4x+k os exactly divisible by x-2 then k =?​

Answer 1

Answer:

Step-by-step explanation:

=> x-2 = 0

=> x = 2

P(x) = x³-3x²+4x+k

=> (2)³-3(2)²+4(2)+k = 0

=> 8-12+8+k = 0

=> -12+k = 0

=> k = 12