Question

(x^3+3x^2-4x)/(x^4-x)
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Answer 1

Answer:

x 22045

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Answer 2

Answer:

(x^3+3x^2-4x)/(x^4-x) = (x+4) / (x²+x+1)

Step-by-step explanation:

=(x³+3x²-4x)/(x⁴-x)

= x(x²+3x-4)/x(x³-1)

= (x²+3x-4)/(x³-1)

Now, factorising the numerator by middle term splitting method

= {x²+(4-1)x-4}/(x³-1)

=( x²-4x-x-4)/x³-1

= x(x-4)-1(x-4)}/(x-1)(x²+1+x)

= (x-1)(x-4)/(x-1)(x²+x+1)

=(x-4)/(x²+x+1)

Hope it will be helpful to you....!!!!