x^3 + 3x^2- 5x + 4 by(x - 1)
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Answer:
(x³+3x²-5x+4) by (x-1)
Step-by-step explanation:
by remainder theorem
zero of (x-1) is
x=1
given that
p(x) = x³+3x²-5x+4
put value of 'X' in p(x)
p(1)=(1)³+3(1)²-5(1)+4
=1+3-5+4
=4-5+4
=8-5
p(1) =3
Remainder is 3
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