Question

x^3+3x^2+9x=1
find x^3+3/x​

Answer 1

Answer:

Step-by-step explanation:

Equation at the end ..

(((x3) - 3x2) - 9x) - 1 = 0

:

Checking for a perfect cube

2.1 x3-3x2-9x-1 is not a perfect cube

Trying to factor by pulling out :

2.2 Factoring: x3-3x2-9x-1

Thoughtfully split the expression at hand into groups, each group having two terms :

Group 1: -9x-1

Group 2: -3x2+x3

Pull out from each group separately :

Group 1: (9x+1) • (-1)

Group 2: (x-3) • (x2)

Step-by-step explanation:

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