x^3-3x^2+9x-5 factorisation
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Answer:
The answer is in the attached photo =>
Step-by-step explanation:
So x^3-3x^2-9x-5
=> (x+1)(x^2-4x-5)
=> (x+1)(x^2+x-5x-5) (Middle term splitting).
=> (x+1)[x(x+1)-5(x+1)]
=>(x+1)(x-5)(x+1)
=> So x=-1 and x=5
There are only 2 values of x as it's 2 zeroes are equal.
And the equation must be-9x instead of +9x.
HOPE IT HELPS.
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