Question

x^3-3x^2-9x-5 factorise

Answer 1

Here's your answer!!

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${x}^{3} - 3 {x}^{2} - 9x - 5$

${x}^{3} + {x}^{2} - 4 {x}^{2} - 4x - 5x - 5$

${x}^{2} (x + 1) - 4x(x + 1) - 5(x + 1)$

$(x + 1)( {x}^{2} - 4x - 5)$

$(x + 1)( {x}^{2} - (5x - 1) - 5)$

$(x + 1)( {x}^{2} - 5x + x - 5)$

$(x + 1) {x}^{2} (x - 5) + 1(x - 5)$

$(x + 1)( x - 5)(x + 1)$
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Hope it helps you!! :)