x^3-3x^2-9x-5
pls Factorise its urgent...
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x^3-3x^2-9x-5
if x=-1 ,this factorise value is zero
x^3-3x^2-9x-5=x^2(x+1)-4x^2-4x-5x-5=x^2(x+1)-4x(x+1)-5(x+1)=(x+1)(x^2-4x-5)=(x+1)(x^2-x+5x-5)=(x+1)(x-1)(x+5)
if x=-1 ,this factorise value is zero
x^3-3x^2-9x-5=x^2(x+1)-4x^2-4x-5x-5=x^2(x+1)-4x(x+1)-5(x+1)=(x+1)(x^2-4x-5)=(x+1)(x^2-x+5x-5)=(x+1)(x-1)(x+5)
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