Question

x^3- 3x^2 $x^3 - 3x^2 - x + 3$-x+3

Answer 1

Answer:

(x-1)(x+1)(x-3)

Step-by-step explanation:

x³-3x²-x+3

Factors of 3 are 1,3

so, p(1) = 1³-3×1²-1+3

= 1-3+2 = 3-3 = 0

Hence, we can say that x-1 is a factor of x³-3x²-x+3

On dividing x³-3x²-x+3 by x-1

we get,

x²-2x-3

So, it becomes

(x-1)(x²-2x-3)

Solving of binomial

= x²-2x-3

= x²-3x+x-3 = x(x-3)+1(x-3) = (x+1)(x-3)

= (x-1)(x+1)(x-3)