Question

x^3+3x^2y+x+3xy^2+y+x^3

Answer 1

Answer:

Hey there !

There is a small error in the question. It is x³ - 3x²y + 3xy² - y³.

So this is of the form of an identity:

( a - b )³ = a³ - 3a²b + 3ab² - b³

Hence we can write the equation as:

x³ - 3x²y + 3xy² - y³ = ( x - y )³

So after factorizing we get, ( x - y )³ .

Hope my answer helped !