Math, asked by haafeelsikkander, 11 months ago

X^3+3xy^2-15x^2-15y^2+72x find extreme values

Answers

Answered by IamIronMan0
5

Step-by-step explanation:

Partial derivative = 0

 \frac{\delta \: f}{\delta \: x} = 3( {x}^{2}  - 10x +  {y}^{2}  + 24) \\  \\ \frac{\delta \: f}{\delta \: y} =6(x - 5)y

Solve for each case y=0 and x = 5

Critical points

( 4 , 0 ) , ( 6 ,0 )

corresponding values

local maxima = 112 and minima =108

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