Question

[{(x^3+3y^2x)/(y^3+3x^2y)} =35/19] find value of x and y​

Answer 1

Answer:

[{(x^3+3y^2x)/(y^3+3x^2y)} = 35/19] find value of x and y. Ask for details; Fo

Click here to get an answer to your question ✍️ Find the value of x+y,if 3x -2y=5 and 3y-2x=3.