Question

x-3+4/2=3x+7/4.




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Answer 1

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Given:-

$x-3+4/2=3x+7/4$

To Find:-

The value of x

Solution:-

$x-3+4/2=3x+7/4$

$= > x - 3x = + 3 - \frac{4}{2} + \frac{7}{4}$

$= > - 2x = \frac{3 \times 4}{1 \times 4} - \frac{4 \times 2}{2 \times 2} + \frac{7}{4}$

$= > - 2x = \frac{12}{4} - \frac{8}{4} + \frac{7}{4}$

$= > - 2x = \frac{12 - 8 + 7}{4}$

$= > - 2x = \frac{13}{4}$

$= > x = \frac{ - 13}{8}$

Answer 2

Answer:

−3+4/2=3x+7/4

To Find:-

The value of x

Solution:-

x-3+4/2=3x+7/4x−3+4/2=3x+7/4

= > x - 3x = + 3 - \frac{4}{2} + \frac{7}{4}=>x−3x=+3−

2

4

+

4

7

= > - 2x = \frac{3 \times 4}{1 \times 4} - \frac{4 \times 2}{2 \times 2} + \frac{7}{4}=>−2x=

1×4

3×4

−

2×2

4×2

+

4

7

= > - 2x = \frac{12}{4} - \frac{8}{4} + \frac{7}{4}=>−2x=

4

12

−

4

8

+

4

7

= > - 2x = \frac{12 - 8 + 7}{4}=>−2x=

4

12−8+7

= > - 2x = \frac{13}{4}=>−2x=

4

13

= > x = \frac{ - 13}{8}=>x=

8

−13