Question

(x+3)/4=(4x-2)/9 ,then find x.​

Answer 1

$\huge \sf \frac{(x + 3)}{4} = \frac{4x - 2}{9} \\ \\ \\ \large \bf{= > 9(x + 3) = 4(4x - 2)} \\ \large \bf{ = > \: 9x + 27 =16x - 8 } \\ \large \bf = > \: \: \: 27 + 8 = 16x - 9x \\ \large \bf = > \: \: \: \: \: \: \: \: \: \: \: 35 = 7x \\ \large \bf = > \: \: \: \: \: \: \: \: \: \: \: 7x = 35 \\ \\ \large \bf = > \: \: \: \: \: \: \: \: \: \: \: \: \: x = \frac{ \cancel{35}}{ \cancel7} = \red5$

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Answer 2

AnswEr :

$\underline{\bigstar\:\textsf{According \: to \: given \: in \: question;}}$

$\normalsize\twoheadrightarrow\sf\frac{(x + 3)}{4} = \frac{(4x - 2)}{9}$

$\scriptsize\tt{\qquad\dag\ Using \: cross \: multiplication n}$

$\normalsize\twoheadrightarrow\sf\ 9(x + 3) = 4(4x - 2)$

$\normalsize\twoheadrightarrow\sf\ 9x + 27 = 16x - 8$

$\normalsize\twoheadrightarrow\sf\ 9x - 16x = -8 - 27$

$\normalsize\twoheadrightarrow\sf\ -7x = -35$

$\scriptsize\tt{\qquad\dag\ Cancel \: negative \: signs \: both\: side}$

$\normalsize\twoheadrightarrow\sf\ 7x = 35$

$\normalsize\twoheadrightarrow\sf\ x = \frac{\cancel{35}}{\cancel{7}}$

$\normalsize\twoheadrightarrow\sf\ x = 5$

$\therefore\:\underline{\textsf{Hence, \: the \: value \: of \: x \: is}{\textbf{\: \: 5 }}}$