Math, asked by rabiyath1, 1 year ago

(x-3)/4+(x-1)/5-(x-2)/3=1

Answers

Answered by ABHISHEKKUMARAGARWAL
10
x-3)/4+(x-1)/5-(x-2)/3=1 

One solution was found :

                   x = 11

Rearrange:

Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation : 

                (x-3)/4+(x-1)/5-(x-2)/3-(1)=0 

Step by step solution :

Step  1  :

x - 2 Simplify ————— 3

Equation at the end of step  1  :

(x-3) (x-1) (x-2) ((—————+—————)-—————)-1 = 0 4 5 3

Step  2  :

x - 1 Simplify ————— 5

Equation at the end of step  2  :

(x - 3) (x - 1) (x - 2) ((——————— + ———————) - ———————) - 1 = 0 4 5 3

Step  3  :

x - 3 Simplify ————— 4

Equation at the end of step  3  :

(x - 3) (x - 1) (x - 2) ((——————— + ———————) - ———————) - 1 = 0 4 5 3

Step  4  :

Calculating the Least Common Multiple :


honeyb1: ans 11
Answered by sushant2505
16
yes,
Take L.C.M. of denominators
this is 60
now,
15(x-3)+12(x-1)-20(x-2)
_________________. =1
60
now,
15x-45+12x-12-20x+40=60
7x=77
x=11

if you don't know how to take LCM please comment
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