Question

|x-3| + |4-x|=1 find where x exist​

Answer 1

Answer:

|x-3| + |4-x| =1

|x-3| + |x-4| = 1 (|4-x| =|-x+4| = |-(x-4)| = |x-4|)

|x-3+x-4| =1 (|a|+ |b| = |a+b|)

2x-7 = +/- 1

2x-7 =1 or 2x-7 = -1

x = (1+7)/2 or x = (-1+7)/2

x = 4 or x = 3

Step-by-step explanation:

Hope it helps