Question

(x-3)^-4(x+3)-5=0 factorise to find the root​

Answer 1

Answer:

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Step-by-step explanation:

(x-3)-4(x+3)-5=0

(x−3)−4(x+3)−5=0

-4x+3

x-3-4x-12-5=0

x−3−4x−12−5=0

x-4x-3x

-3x-3-12-5=0

−3x−3−12−5=0

12-3-15

-3x-15-5=0

−3x−15−5=0

5-15-20

-3x-20=0

−3x−20=0

20

-3x=20

−3x=20

-3

x=\frac{20}{-3}

x=

−3

20

\frac{20}{-3}\approx -6.666666667

-\frac{20}{3}\approx -6.666666667

x=-\frac{20}{3}

x=−

3

20