Question

x^3+4x-1=0 for this equation find alpha^3+beta^3+gamma^3​

Answer 1

Answer:

3

Step-by-step explanation:

a+b+c =0

substitute a ,b,c seperatly in the equation add them we get a^3+b^3+c^3 =3-4(a+b+c) we know a+b+c=0

Answer 2

hey buddy here is your answer

3 is a correct answer