Question

x^3-4x^2-x+1=(x-2)^3​

Answer 1

Answer:

${x}^{3} - 4 {x}^{2} - x + 1 = {(x - 2)}^{3} \\ {x}^{3} - 4 {x}^{2} - x + 1 = {x}^{3} - 8 - 6 {x}^{2} + 12x \\ {x}^{3} - 4 {x}^{2} - x + 1 - {x}^{3} + 8 + 6 {x}^{2} - 12x = 0 \\ 2 {x }^{2} - 13x + 9 = 0$