x^3 + 4x – 3 by (x + 5)
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x^3+4x-3 is not divisible by (x+5) since if we put x = -5 in x^3+4x-3 we get
(-5)^3 + 4(-5) - 3
= -125–20–3
=-148
≠ 0
So we get the remainder -148 if x^3+4x-3 is divided by x+5
To show the division procedure we will apply division method
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