Question

X^3-4x+3
Odd or Even?

Answer 1

Answer:

it is odd ...........................................

Answer 2

Answer:

Solution:

We know that,

sec2θ – tan2θ = 1

(sec θ + tan θ) (sec θ – tan θ) = 1

(7) (sec θ – tan θ) = 1 …[sec θ + tan θ = 7; (Given)

∴ sec θ – tan θ = 17Solution:

We know that,

sec2θ – tan2θ = 1

(sec θ + tan θ) (sec θ – tan θ) = 1

(7) (sec θ – tan θ) = 1 …[sec θ + tan θ = 7; (Given)

∴ sec θ – tan θ = 17Solution:

We know that,

sec2θ – tan2θ = 1

(sec θ + tan θ) (sec θ – tan θ) = 1

(7) (sec θ – tan θ) = 1 …[sec θ + tan θ = 7; (Given)

∴ sec θ – tan θ = 17Solution:

We know that,

sec2θ – tan2θ = 1

(sec θ + tan θ) (sec θ – tan θ) = 1

(7) (sec θ – tan θ) = 1 …[sec θ + tan θ = 7; (Given)

∴ sec θ – tan θ = 17Solution:

We know that,

sec2θ – tan2θ = 1

(sec θ + tan θ) (sec θ – tan θ) = 1

(7) (sec θ – tan θ) = 1 …[sec θ + tan θ = 7; (Given)

∴ sec θ – tan θ = 17Solution:

We know that,

sec2θ – tan2θ = 1

(sec θ + tan θ) (sec θ – tan θ) = 1

(7) (sec θ – tan θ) = 1 …[sec θ + tan θ = 7; (Given)

∴ sec θ – tan θ = 17Mark me BRAINLEIST

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