Question

(x^3-4x+8) (3x+4) find the product​

Answer 1

Answer:

$( {x}^{3} - 4x + 8)(3x + 4) \\ 3 {x}^{4} + 4 {x}^{3} - 12 {x}^{2} - 16x + 24x + 32 \\ 3 {x}^{4} + 4 {x}^{3} - 12 {x}^{2} + 8x + 32$