Question

x^3-4x find the zeros of the polynomial?

Answer 1

• Answer :-

→ x³ - 4x = 0

→ x(x² - 4) = 0

→ x[(x)² - (2)²] = 0

→ x(x + 2)(x -2) = 0

• x = 0
• (x + 2)(x - 2) = 0
• x = - 2 and x = 2

Answer 2

Answer:

$x {3}^{} - 4x = 0 \\ \\ x(x {}^{2} - 4) = 0 \\ \\ x {}^{2} - 4 = 0 \\ \\ x {}^{2} = 4 \\ \\ x = + - \sqrt{4} \\ \\ x = + 2 \: and \: x = - 2.$

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