Math, asked by questions364, 11 months ago

(X+3/4y-4z)^2
please answer​

Answers

Answered by DevyaniKhushi
65

 {(x +  \frac{3}{4y} - 4z )}^{2}  \\  \\  {(x)}^{2}  +  {( {\tiny{\frac{3}{4y} }})}^{2}  +  {( - 4z)}^{2}  + 2[(x)( {\tiny{\frac{3}{4y}}} ) + ( {\tiny{\frac{3}{4y}}} )( - 4z) + ( - 4z)(x)] \\  \\  {x}^{2}  + { \tiny{\frac{9}{ {16y}^{2} }}}+  {16z}^{2}  + 2[ { \tiny{\frac{3x}{4y}}} + ( { \tiny{\frac{ - 3z}{y}}} ) + ( - 4zx) ] \\  \\  {x}^{2} +  { \tiny{\frac{9}{ {16y}^{2} }}} +  {16z}^{2}  + { \tiny{ \frac{3x}{2y} }} - { \tiny{ \frac{6z}{y} }} - 8zx

<marquee>MARK BRAINLIEST

Answered by poonamkum794
4

Step-by-step explanation:

(x+

4y

3

−4z)

2

(x)

2

+(

4y

3

)

2

+(−4z)

2

+2[(x)(

4y

3

)+(

4y

3

)(−4z)+(−4z)(x)]

x

2

+

16y

2

9

+16z

2

+2[

4y

3x

+(

y

−3z

)+(−4zx)]

x

2

+

16y

2

9

+16z

2

+

2y

3x

y

6z

−8zx

< marquee > MARK BRAINLIEST<marquee>

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