Question

(x^3 + 5x^2 + 6x) and (2x^3 + 4x^2)​

Answer 1

Step-by-step explanation:

Your answer:

$\dagger \: \: \: { ( {x}^{3} + {5x}^{2} + 6x)(2 {x}^{3} + {4x}^{2} )}$

$= {x}^{3} ( {2x}^{3} + {4x}^{2} ) + 5 {x}^{2} (2 {x}^{3} + {4x}^{2} ) + 6x( {2x}^{3} + {4x}^{2} )$

[ multiply the terms using distributive method ]

$= 2 {x}^{3 + 3} + {4x}^{3 + 2} + {10x}^{2 + 3} + {20x}^{2 + 2} + {12x}^{ 1+ 3} + 24 {x}^{1 + 2}$

[ now add the exponents ]

$= 2 {x}^{6} + 4 {x}^{5} + {10x}^{5} + {20x}^{4} + {12x}^{4} + {24}x^{3}$

$\cdot \: {2x}^{6} + ( {4x + 10x)}^{5} + (20x + 12x {)}^{4} + 24 {x}^{3}$

$= {2x}^{6} + {14x}^{5} + {32x}^{4} + 24 {x}^{3}$