x^3+5x^2+7x+3 ; - 3, 2-1, - 1
kamalmani2014:
what do we have to do in this?
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alpha +beta+gamma=-b/a=-(5)/1
alpha*beta+beta*gama+gamma*alpha = c/a=7/1
alpha*beta*gamma=-d/1=-(3)
this is the relation between the coefficients and zeroes and it is a cubical polynomial..
hope it will hel you :)
alpha*beta+beta*gama+gamma*alpha = c/a=7/1
alpha*beta*gamma=-d/1=-(3)
this is the relation between the coefficients and zeroes and it is a cubical polynomial..
hope it will hel you :)
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1
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