Question

x^3+64y^3+12x^2y+48xy^2

Answer 1

Hey,

x³ + 64y³ + 12x²y + 48xy² = 0

⇒(x)³ + (4y)³ + 3(x²)(4y) + 3(x)(4y)² = 0

⇒ (x + 4y)³ = 0

⇒ (x + 4y) = 0

HOPE THIS HELPS YOU

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