X^3+64Y^3 factorice it
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Since both terms are perfect cubes, factor using the difference of cubes formula, a3−b3=(a−b)(a2+ab+b2)a3-b3=(a-b)(a2+ab+b2) where a=xa=x and b=4yb=4y.
(x−(4y))(x2+x(4y)+(4y)2)
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