Question

x^3+ 6x^2 = 0, value of x

Answer 1

$<h2>Hi Morning DUDE</h2>$

$<h3> Divide both sides by x^2 GIVEN: [tex]x ^{3} + 6x ^{2} = 0$

$x ^{3} \div x ^{2} + 6x ^{2} \div x ^{2} = 0$

$x + 6 = 0$

$x = - 6$

so, the value of X is -6.