x^3 + 6x^2 + 10 x + 16 by ( x + 3)
Answers
Answer:
Step-by-step explanation:
Given (x^3)-6(x^2)+11x-6=0
x^3-3x^2-3x^2+11x-6=0
x^2(x-3)-(3x^2-11x+6)=0
x^2(x-3)-(3x^2-9x-2x+6)=0
x^2(x-3)-(3x(x-3)-2(x-3))=0
x^2(x-3)-[(x-3)(3x-2)]=0
(x-3)(x^2-3x+2)=0
(x-3)(x^2-2x-x+2)=0
(x-3)(x(x-2)-1(x-2))=0
(x-3)(x-2)(x-1)=0
7.2k Views ·
Your feedback is private.
Is this answer still relevant and up to date?
How do I find other roots if x=1 is one root of a polynomial x3−6x2+11x−6=0?
How do you solve this equation, x2-6x-6=0, if x=3√2+3√4?
How do I factor x^4+6x^3+11x^2+6x+1?
How do I factor 6x4−x3−35x2−6x+22?
How can I solve this math problem? [x] +x-3/2=0
Given (x^3)-6(x^2)+11x-6=0
let x=1 is the factor of the equation
1 |1 -6 11 -6
| 0 1 -5 6
-----------------------
1 -5 6 0
hence x=1 is one of the factor
=>x^2-5x+6=0
=>x^2-2x-3x+6=0
=>x(x-2)-3(x-2)=0
=>(x-2)(x-3)=0
hence factor are (x-1)(x-2)(x-3)=0
9.9k Views ·
Your feedback is private.
Is this answer still relevant and up to date?
x^3 - 6 x^2 +11x - 6 = 0
x^3 - 3 x^2 - 3 x^2 +11x - 6 = 0
X^2 (x - 3) - (3 x^2 -11x + 6) = 0
X^2 (x - 3) - (3x -2) (x - 3) = 0
(x - 3) (x^2 - 3x + 2) = 0
(x - 3) (x - 2) (x - 1) = 0
Hope this helps us
Please mark me brainliest
