Math, asked by gmander222, 10 months ago

(x^3+6x^2+12+13x)÷(x+3)

Answers

Answered by sudarsana69
4

Answer:x=3

x=23−−7

​​=23−i7

​​=1.5000−1.3229i

x=23+−7

​​=23+i7

​​=1.5000+1.3229i

Step-by-step explanation:(1): "x2"   was replaced by   "x^2".  1 more similar replacement(s). (((x3) -  (2•3x2)) +  13x) -  12  = 0

2.1    x3-6x2+13x-12  is not a perfect cube  2.2      Factoring:  x3-6x2+13x-12

Thoughtfully split the expression at hand into groups, each group having two terms :

Group 1:  13x-12

Group 2:  -6x2+x3

Pull out from each group separately :

Group 1:   (13x-12) • (1)

Group 2:   (x-6) • (x2)

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