Question

x^3-6x^2+2x-4 by 1-3x (by the long division method)​

Answer 1

Step-by-step explanation:

when we divide f(x) by g(x)

g(x) = 3x-1

so root = 1/3

then by remainder theorem

f(1/3)= (1/3)^3-6*(1/3)^2+2*1/3-4

= 1/27-6/9+2/3-4

= 1/27-4

= 1-27*4/27

= -107/27