Question

x^3-6x^2+2x-4 divided by 1-3/2x by long division method​

Answer 1

Answer:

-835

Step-by-step explanation:

The zero of g(x)=1−2x is x=21

Now, by remainder theorem the remainder should be f(21)

∴f(21)=(21)3−6(21)2+2(21)−4

               =(81)−6(41)+1−4

               =(81)−(46)−3

               =81−12−24

               =−835

mark me brainlist