Question

x^3-6x^2+9x-4=0 find the value of x​

Answer 1

Hi...

${x}^{3} - 6 {x}^{2} + 9x - 4 = 0$

▪Put x=1

▪${1}^{3} - 6 {(1)}^{2} + 9(1) - 4$

▪$1 - 6 + 9 - 4$

▪$0$

we get answer 0 ..so,

▪x=1

similarly we can find other zeroes......

#THANKS