Question

(x^3+6x^2-x-18) ÷ (x+2)​

Answer 1

Answer:

Please mark me the brainliast

Answer 2

Answer:

let, x+2=0

x=-2

So A/q,

x^3+6x^2-x-18

let put the value of x as -2

So,(-2)^3+6(-2)^2-(-2)-18

= -8+24+2-18

= 16-16

So,we can cut both +6 and -6.

= 0 Ans

Thank you