Math, asked by sanjits6269, 4 months ago

(x-3)(6x^2-x-35)/(x-4)(3x^2-2x-21)

Answers

Answered by Anonymous
4

Answer:

 \frac{ (x - 3)( {6x}^{2}  - x - 35)}{(x - 4)({3x}^{2} - 2x - 21) }

 \frac{ \:  \:x({6x }^{2}  - x - 35) - 3({6x}^{2}  - x - 35)  \:  \: }{x(3 {x}^{2} - 2x - 21) - 4 (3 {x}^{2} - 2x - 21)}

 \frac{ \:  6 {x}^{3}  -  {x}^{2}  - 35x  -  18 {x}^{2} + 3x + 105  }{{3x  }^{3} - {2x}^{2} - 21x - 12 {x}^{2}  + 8x + 84  }

 \frac{ \:  6 {x}^{3}  - 19 {x}^{2}  - 32x + 105 }{3 {x}^{3} - 14 {x}^{2} - 13x + 84  }

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