Question

x^3+6x-7=0 find the factor


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Answer 1

Answer:

x-1 and x^2+1x+7

Step-by-step explanation:

do error and trial methods

putting the value of x as 1 we get

( 1 )^3+6(1)-7

= 1+6-7

= 0

then the first factor is x-1

Now, dividing x^3+6x-7 by x-1 we get

x-1 ) x^3+6x-7 ( x^2+1x+7

x^3-x^2

- +

x^2+6x

x^2 -1x

- +

7x-7

7x-7

- +

0

hence,

x^3+6x-7 = ( x-1)(x^2+1x+7)