Question

(x+3)/7-(2x-5)/3=(3x-5)/5-25 solve it fast
Pls ans it correctly​

Answer 1

Answer:

The value of x is 25.

Step-by-step explanation:

Given : Equation \frac{x+3}{7}-\frac{2x-5}{3}=\frac{3x-5}{5}-25

7

x+3

−

3

2x−5

=

5

3x−5

−25

To find : Solve the equation ?

Solution :

Equation \frac{x+3}{7}-\frac{2x-5}{3}=\frac{3x-5}{5}-25

7

x+3

−

3

2x−5

=

5

3x−5

−25

Taking LCM,

\frac{3(x+3)-7(2x-5)}{21}=\frac{3x-5-125}{5}

21

3(x+3)−7(2x−5)

=

5

3x−5−125

\frac{3x+9-14x+35}{21}=\frac{3x-5-125}{5}

21

3x+9−14x+35

=

5

3x−5−125

\frac{-11x+44}{21}=\frac{3x-130}{5}

21

−11x+44

=

5

3x−130

Cross multiply,

5(-11x+44)=21(3x-130)5(−11x+44)=21(3x−130)

-55x+220=63x-2730−55x+220=63x−2730

63x+55x=2730+22063x+55x=2730+220

118x=2950118x=2950

x=\frac{2950}{118}x=

118

2950

x=25x=25

Therefore, The value of x is 25.

Answer 2

Answer:

x = 2950/118.

Step-by-step explanation:

(x+3)/7 - (2x-5)/3 = (3x-5)/5 - 25

[3x+9-14x+35]/21 = (3x-5-125)/5

(-11x+44)/21 = (3x-130)/5

-55x+220 = 63x-2730

220+2730 = 63x+55x

2950 = 118x

x = 2950/118.